By William Paulsen

By integrating using hole and *Mathematica*^{®}, **Abstract Algebra****: An Interactive Approach** provides a hands-on method of studying approximately teams, earrings, and fields. every one bankruptcy comprises either hole and *Mathematica* instructions, corresponding *Mathematica* notebooks, conventional workouts, and a number of other interactive desktop difficulties that make the most of hole and *Mathematica* to discover teams and rings.

Although the ebook supplies the choice to exploit know-how within the school room, it doesn't sacrifice mathematical rigor. It covers classical proofs, similar to Abel’s theorem, in addition to many graduate-level themes no longer present in most traditional introductory texts. the writer explores semi-direct items, polycyclic teams, Rubik’s Cube^{®}-like puzzles, and Wedderburn’s theorem. He additionally contains challenge sequences that let scholars to delve into fascinating subject matters intensive, together with Fermat’s sq. theorem.

This leading edge textbook indicates how scholars can larger take hold of tricky algebraic recommendations by using machine courses. It encourages scholars to test with a variety of purposes of summary algebra, thereby acquiring a real-world viewpoint of this area.

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**Extra info for Abstract Algebra: An Interactive Approach**

**Sample text**

This shows that every column in the multiplication table contains one and only one of each element. 11 If two of Terry’s dance steps are chosen at random, what are the chances that these two dance steps will commute? Hint: There are 36 ways of choosing two dance steps. Count the number of combinations that satisfy the equation x · y = y · x. 15: Construct a multiplication table for the set of numbers modulo n. 4 shows that the multiplication table has the same properties as Terry’s dance steps.

There is an identity dance step. 5. Every dance step has an inverse. With just these properties, we are able to prove the following. 1 If y is an inverse of x, then x is the only inverse of y. PROOF Let z be any inverse of y. Consider the product x·y·z. According to the associative property, x · (y · z) = (x · y) · z. 4 Abstract Algebra: An Interactive Approach On the left side, we see that y · z is an identity element, so x · (y · z) = x. But on the right side, we find that x · y is an identity element, so (x · y) · z = z.